Final answer:
When a fluorophore absorbs orange excitation light, it emits light at a longer wavelength, which will be in the red spectrum of the visible light. Hence, the correct emission color is red light.
Step-by-step explanation:
The question you've asked is about fluorescence microscopy and the emission wavelength of a fluorophore that requires orange excitation light. Fluorescent compounds absorb light at one wavelength (the excitation wavelength) and then emit light at a longer wavelength, which is the emission wavelength. In fluorescence microscopy, when a fluorophore is excited by orange light, we can expect it to emit light in a color with a longer wavelength, which means it will emit red light.
Fluorescence is a natural phenomenon that is used in microscopy to create contrast between structures or molecules within a specimen. The excitation light, generally a form of electromagnetic radiation with a short wavelength like ultraviolet or blue light, is absorbed by the fluorophores and re-emitted as visible light with a longer wavelength.
In summary, if a fluorophore absorbs orange light, which is in the middle of the visible spectrum, its emission is going to be at a longer wavelength, hence in red light, which is the correct answer: c. Red light.