Final answer:
By converting the kinetic energy into potential energy, we calculated the height from which a 6 kg rock fell to be approximately 29 meters before impacting the ground at 24 m/s. Therefore correct option is A
Step-by-step explanation:
To determine from what height a 6 kg rock falls when it hits the ground at 24 m/s, we use the equation for gravitational potential energy and kinetic energy.
The potential energy at the beginning (mgh) is equal to kinetic energy just before impact ½mv², where m is mass, g is the acceleration due to gravity (9.8 m/s²), h is the height, v is the velocity, and ½ is a constant representing 'one half'.
Solving for h, we rearrange the equation to h = v² / (2g).
Plugging in the values, h = (24 m/s)² / (2 * 9.8 m/s²)
= 576 / 19.6
= 29.4 m, which we can round to the nearest whole number, giving us a height of approximately 29 m.