Question

What is the final temperature when 100 g of iron at 90°C is placed in 400 g of water at 25°C? The specific heat capacity of iron 0.45 J/g*K and the specific heat capacity of water is 4.184 J/g*K.

O 26.7 °C
O 93.7 °C
O 30.2°C
O 21.1°C

Answer 1

The final temperature when 100 g of iron at 90°C is placed in 400 g of water at 25°C is 26.74°C (option A).

The temperature in a calorimetry procedure can be calculated using the formula;

Q = mc∆T

Where;

Q = quantity of heat absorbed or released

m = mass

C = specific capacity

∆T = change in temperature

Q(water) = -Q(metal)

400 × 4.184 × (T - 25) = 100 × 0.45 × -{25 - 90})

1,673.6T - 41,840 = 2925

1,673.6T = 44,765

T = 26.74°C