The decelerating force that caused the block of wood to stop, given that it moved 10 cm, is -1166.4 N
How to calculated the decelerating force?
To answer this question, we shall begin by calculating the decleration of the block of wood. This is shown below:
- Initial velocity (u) = 360 m/s
- Distance (s) = 10 cm = 10 / 100 = 0.1 m
- Final velocity (v) = 0 m/s
- Deceleration of block of wood (a) = ?
v² = u² + 2as
0² = 360² + (2 × a × 0.1)
0 = 129600 + 0.2a
0 - 129600 = 0.2a
-129600 = 0.2a
Divide both side by 0.2
a = -129600 / 0.2a
a = -648000 m/s²
Finally, we shall calculate the decelerating force that caused the block to stop. Detail; below:
- Mass of block (m) = 1.8 g = 1.8 / 1000 = 0.0018 Kg
- Deceleration of block (a) = -648000 m/s²
- Decelerating force (F) =?
Decelerating force = mass × deceleration
= 0.0018 × -648000
= -1166.4 N