Question

let x random variables that possesses a binomial distribution with p=0.7 and n=15 using the binomial of the distribution round solution to four decimal places

Answer 1

It is given that the satisaction is 72% so p=0.72 and 5 people are chosen at random so n=5.

Part a:The probability distribution is given by:

Part b:The mean is given by:

`\mu=np=0.72*5=3.6`

Part c: The standard deviation is given by:

`\sigma=\sqrt[]{npq}=\sqrt[]{5*0.72*0.28}=1.00399\approx1.004`