Question

Consider the interface between two regions along the YZ plane. Both regions have non-zero, but small finite conductivity. If the magnetic field intensity in region-1 is given by: Hˉ1=−2x^+3y^+z^, find H2 and B2. The parameters of the two regions are: ϵr1=2,μr1=1;ϵr2=3,μr2=10.

Answer 1

To find H2 and B2, we need to consider the interface between two regions along the YZ plane. In region 1, the magnetic field intensity is given by Hˉ1 = −2x^ + 3y^ + z^. Region 1 has parameters ϵr1 = 2 and μr1 = 1. In region 2, the parameters are ϵr2 = 3 and μr2 = 10.

Step-by-step explanation:

To find H2 and B2, we need to consider the interface between two regions along the YZ plane. In region 1, the magnetic field intensity is given by Hˉ1 = −2x^ + 3y^ + z^.

Region 1 has parameters ϵr1 = 2 and μr1 = 1. In region 2, the parameters are ϵr2 = 3 and μr2 = 10.

To calculate H2, we can use the relation H1 = ϵ1E1/μ1. Solving for E1 and substituting the values, we get E1 = (H1 × μ1)/ϵ1. Plugging in values, we find E1 = -(2x^ + 3y^ + z^) × 1/2.

Similarly, we can calculate B2 using the relation B2 = μ2H2. Solving for H2 and substituting the values, we get H2 = B2/μ2. Plugging in values, we find H2 = (2x^ + 3y^ + z^) × 1/10.