Question

If the intrinsic stand-off ratio (η) for a UJT is 0.6 \& the resistance between the two bases is 5 KΩ(Rb1 and Rb2). Find the resistance of each base.

Answer 1

To find the resistance of each base in a UJT with an intrinsic stand-off ratio of 0.6 and a total base resistance of 5 kΩ, you calculate Rb1 as 0.6 times the total resistance and Rb2 as 0.4 times the total resistance, yielding Rb1 = 3000Ω and Rb2 = 2000Ω.

Step-by-step explanation:

The student was asked to find the resistance of each base (Rb1 and Rb2) for a Unijunction Transistor (UJT) given the intrinsic stand-off ratio (η) and the total resistance between the two bases (Rb). The intrinsic stand-off ratio is defined as η = Rb1 / (Rb1 + Rb2), and the question states that η is 0.6 and the total resistance (Rb) is 5 kΩ.

First, we need to express Rb1 and Rb2 in terms of η and Rb. We know that:

• Rb1 = η × (Rb)
• Rb2 = (1 - η) × (Rb)

Substituting the values given:

• Rb1 = 0.6 × 5000Ω = 3000Ω
• Rb2 = (1 - 0.6) × 5000Ω = 0.4 × 5000Ω = 2000Ω

Therefore, the resistance of each base is as follows: Rb1 is 3000Ω and Rb2 is 2000Ω.