Final answer:
To determine the cutoff frequency (fe) for a low-pass RC filter, the standard formula fe = 1/(2πRC) is used. Without the correct unit for capacitance, the calculated fe may not be valid. However, assuming the capacitance is in farads, the calculation results in a very low cutoff frequency, which most likely indicates an error in the unit of capacitance provided.
Step-by-step explanation:
To determine the cutoff frequency (fe) of a low-pass RC filter with a resistance (R) of 110Ω and a capacitance (C) of 0.5 henryfarads (which seems to be a typo, as 'hf' is not a standard unit for capacitance, it should likely be 'farads' or 'microfarads'), the following formula is used:
fe = 1/(2πRC)
Assuming 'hf' is intended to be 'farads', the cutoff frequency would be:
fe = 1/(2π * 110Ω * 0.5F) = 1/(2π * 55) ≈ 1.45 x 10^-3 Hz
However, if 'hf' is intended to be 'microfarads' (μF), then the capacitance would be 0.5μF and calculation will be:
fe = 1/(2π * 110Ω * 0.5x10^-6F) ≈ 2.90 x 10^3 Hz.
The calculated value might not make sense practically with such high capacitance value as 0.5 farads; it is probably in microfarads. Please confirm the correct capacitance unit for an accurate calculation.