Final answer:
The specific heat of the block, calculated using the formula Q = mcΔT, is 240 J/kg°C.
Step-by-step explanation:
To calculate the specific heat of the block in the question, we use the formula for heat transfer: Q = mcΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Given the values of Q = 2.4 • 106 joules, m = 1000.0 kg, and ΔT = 720.0 °C - 710.0 °C = 10.0 °C, we can solve for c (specific heat capacity).
Using the formula, c = Q / (mΔT), we get:
c = 2.4 • 106 J / (1000.0 kg × 10.0 °C) = 240 J/kg°C
Therefore, the specific heat of the block is 240 J/kg°C.