Final answer:
The energy content of a 3.0 V battery that powers a flashlight using 2.0 A of current for 3.00 hours is 64800 joules. This is calculated by using the formula Energy = Power × Time, with Power being the product of Voltage and Current.
Step-by-step explanation:
To determine the energy content of the battery powering a flashlight, we can use the relationship between power, voltage, and current. Power (in watts) is the product of voltage (in volts) and current (in amperes). The formula is Power = Voltage × Current. Therefore, if the battery has a voltage of 3.0 V and the flashlight uses 2.0 A of current, the power can be calculated as follows:
Power = 3.0 V × 2.0 A = 6.0 watts
To find the energy content, we need to consider the time the battery lasts, which is given as 3.00 hours. The energy consumed (in joules) can be calculated by multiplying the power by the time in seconds (1 hour = 3600 seconds):
Energy = Power × Time = 6.0 watts × (3.00 hours × 3600 seconds/hour)
Energy = 6.0 W × 10800 s = 64800 joules (J)
Therefore, the energy content of the battery is 64800 J.