Final answer:
The charged particle experiences a force calculated by the equation F = qvB. With the given values, the force experienced by the charge as it enters the magnetic field is 0.1368 N.
Step-by-step explanation:
The force experienced by a particle with a charge of 6.0 • 10-5 C moving with a velocity of 760 m/s perpendicular to a 3.0 T magnetic field can be calculated using the formula:
F = q • v • B • sin(θ)
Where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. Since the particle is moving perpendicular to the field, the angle is 90 degrees, so sin(90) = 1. Substituting the given values into the formula, we have:
F = (6.0 • 10-5 C) • (760 m/s) • (3.0 T) • 1 = 1.368 N
Therefore, the force experienced by the charge as it enters the magnetic field is approximately 1.368 N.