Question

A skydiver falls out of a plane from rest, and experiences no air resistance. Eventually, this skydiver reaches a velocity of 33 m/s. How much time did this take? *

Answer 1

the time taken for the motion is 3.37 s

Step-by-step explanation:

Given;

initial velocity of the skydiver, u = 0

final velocity of the skydiver, v = 33 m/s

The time taken for the motion is calculated as;

v = u + gt

33 = 0 + 9.8t

33 = 9.8t

t = 33 / 9.8

t = 3.37 s

Therefore, the time taken for the motion is 3.37 s