Final answer:
The acceleration of the car that starts from rest and covers 100 meters in one second is calculated using the kinematic equation for uniformly accelerated motion, resulting in an acceleration of 200 m/s².
Step-by-step explanation:
To find the acceleration of a car that starts from rest and covers a distance of 100 meters in one second, we can use the kinematic equation for uniformly accelerated motion:
S = ut + \frac{1}{2}at^2
Where:
- S is the distance covered
- u is the initial velocity (which is 0 since the car starts from rest)
- t is the time (which is 1 second)
- a is the acceleration (which we need to find)
Substituting the given values, we get:
100 = 0\times1 + \frac{1}{2}\times a \times (1)^2
This simplifies to:
100 = \frac{1}{2} \times a
So,
a = 200 m/s2
The acceleration of the car is 200 m/s2.