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How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25 degrees Celsius to 50 degrees Celsius?

User Adverbly
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Final answer:

To raise the temperature of 100.0 grams of water from 25°C to 50°C, 10.46 kJ of heat is needed, using the specific heat capacity of water (4.184 J/g°C) and the formula q = m × c × ΔT.

Step-by-step explanation:

Calculating Heat Required to Raise Water Temperature

To calculate the amount of heat needed to raise the temperature of a substance, we can use the formula:

q = m × c × ΔT

Where:

q is the heat energy in Joules (J) or kilojoules (kJ)

m is the mass of the substance in grams (g)

c is the specific heat capacity (4.184 J/g °C for water)

ΔT is the change in temperature in degrees Celsius (°C)

For 100.0 grams of water, the amount of heat needed to raise the temperature from 25°C to 50°C is:

q = (100.0 g) × (4.184 J/g°C) × (50°C - 25°C)

q = (100.0 g) × (4.184 J/g°C) × (25°C)

q = 10,460 J

Since 1 kJ = 1,000 J, q = 10.46 kJ. Therefore, 10.46 kJ of heat is needed to raise the temperature of 100.0 grams of water from 25°C to 50°C.

User Chansik Im
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