Final answer:
The molecular formula for a compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole is C4H8O2, which corresponds to B) C4O2H8.
Step-by-step explanation:
The compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole can be determined by calculating the number of empirical formula units in the molar mass. The empirical formula mass for C2OH4 is 12(2) + 16 + 1(4) = 44 g/mol. Since the molar mass is 88 g/mol, this is exactly twice the mass of the empirical formula, so the molecular formula contains two empirical units. Therefore, the molecular formula of the compound is C4H8O2, which corresponds to option B) C4O2H8.