Final answer:
To expand log6 (2y-3/y), we use the Quotient Rule of Logarithms which states that the logarithm of a quotient is the difference of the logarithms of the numerator and the denominator, resulting in log6 (2y-3) - log6 (y).
Step-by-step explanation:
To write an expanded expression equivalent to log6 (2y-3/y) using the Quotient Rule of Logarithms, we need to apply the rule that states the logarithm of a quotient is the difference between the logarithms of the numerator and the denominator.
The Quotient Rule of Logarithms tells us that:
loga (x/y) = loga x - loga y
Therefore, for log6 (2y-3/y), we split the logarithm into two parts:
log6 (2y-3) - log6 (y)
Note that parentheses are used around the logarithm functions when dealing with additions or subtractions to avoid confusion.