Final answer:
The solubility of Mg(OH)2 is 16 times lower in 0.1 M NH3 compared to pure water due to the complex formation with NH3.
Step-by-step explanation:
The solubility of Mg(OH)2 in 0.1 M NH3 is 16 times lower than its solubility in pure water.
This is because NH3 is a weak base and can react with Mg(OH)2 to form a complex ion, Mg(NH3)42+.
This complex ion reduces the concentration of Mg2+ and OH- ions in the solution, thereby decreasing the solubility of Mg(OH)2.