Question

At the bottom of the first hill, the 300 kg car is traveling 39.6 m/s. What is the kinetic energy of the car at this point? (ignore friction forces)

Answer 1

1st option: 235,000 J

Explanation:

Given:

Mass (m) = 300 kg

Speed (v) = 39.6 m/s

We can calculate the kinetic energy using the following formula:

`\begin{gathered} E_K=(1)/(2)mv^2 \\ \text{ We replacing:} \\ E_K=(1)/(2)\cdot300\cdot39.6^2 \\ E_K=235224\cong235000\text{ J} \end{gathered}`

The kinetic energy is 235000 J.