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The equation of line u is x–2y=20. Line v includes the point (3, – 3) and is perpendicular to line u. What is the equation of line v

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Answer:

Line v equation: y = -2x + 3

Explanation:

Relationship between the slopes of perpendicular lines:

  • The slopes of perpendicular are negative reciprocals of each other.

This is shown by the formula m2 = -1 / m1, where:

  • m2 is the slope of the line we're trying to find,
  • and m1 is the slope of the line we're given.

Identifying the form of x - 2y = 20 and converting to slope-intercept form:

x - 2y = 20 is in the standard form of a line, whose general equation is given by:

Ax + By = C, where:

  • A, B, and C are constants.

The general form of the slope-intercept form is given by:

y = mx + b, where:

  • m is the slope,
  • and b is the y-intercept.

Thus, we can convert x - 2y = 20 to slope-intercept form by isolating y:

(x - 2y = 20) - x

(-2y = -x + 20) / -2

y = 1/2x - 10

Thus, the slope of line u is 1/2.

Finding the slope of line v:

Now, we can find the slope of line v by substituting 1/2 for m1 in the perpendicular slope formula:

m2 = -1 / (1/2)

m2 = -1 * 2

m2 = -2

Thus, the slope of line v is -2.

Finding the y-intercept of line v and finding the equation of line v (in slope-intercept form):

Now, we can find the y-intercept of line v by substituting (3, -3) for (x, y) and -2 for m in the slope-intercept form:

-3 = -2(3) + b

(-3 = -6 + b) + 6

3 = b

Thus, the y-intercept of ilne v is 3.

Therefore, the equation of line v (in slope-intercept form) is y = -2x + 3.

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