Final answer:
An allopolyploid resulting from the hybridization of Species A (2n=12) and Species B (2n=14) will have a total of 52 chromosomes. This is calculated by adding the diploid numbers of both species and then multiplying by two, (12 + 14) × 2, as the allopolyploid organism will contain two complete sets from each species.
Step-by-step explanation:
When Species A (2n=12) and Species B (2n=14) mate to produce an allopolyploid, we consider the total number of chromosomes from both species in their diploid state.
An allopolyploid organism is formed through the hybridization of two different species, combining their chromosome sets. Since Species A has a diploid number of 12 and Species B has a diploid number of 14, the allopolyploid would have two complete sets from each species for a total of 4 sets. This equates to (12 + 14) × 2, resulting in a total of 52 chromosomes in the allopolyploid organism.
Example:
- Species A diploid gamete: 12 chromosomes
- Species B diploid gamete: 14 chromosomes
- Total in allopolyploid (tetraploid): (12 + 14) × 2 = 52 chromosomes
This is because the term 'tetra' refers to four, indicating the presence of four sets of chromosomes.