Question

Please help me with this problem I am not able to help my son to understand we keep getting it wrong please help.The function y=−16x^2+v0x models Lindy's height in feet above a trampoline x seconds after she jumps straight up. In the equation of the function, v0 is her initial velocity in feet per second. Lindy lands back on the trampoline 1 second after she jumps. What is the value of v0?Enter your answer in the box.v0= ft/s

Answer 1

Step-by-step explanation:

We are given the function which models Lindy's height x seconds after she jumps straight up a trampoline. The function is expressed as;

`y=-16x^2+v_0`

Where x is the time in seconds after she jumps, and v_0 is the initial velocity. The result of the function is her height after jumping with the given time x.

If she lands back on the trampoline one second after she jumps, then she is at a height of zero.

The function can now be re-written as follows;

`\begin{gathered} \text{With;} \\ x=1\text{ (time)} \\ y=0\text{ (height)} \end{gathered}`
`0=-16(1)^2+v_0`

We can now simplify;

`-16(1)^2+v_0=0`

Add

`-16(1)^2`

to both sides;

`\begin{gathered} v_0=16(1)^2 \\ v_0=16 \end{gathered}`

Therefore;

ANSWER:

The value of v_0( her initial velocity) is;

`v_0=16`