Question

Calculate the grams of solute needed to prepare each of the following: 1.00 L of a 4.90 M NaOH solution.

a) 200.05 g
b) 85.00 g
c) 19.84 g
d) 9.80 g

Answer 1

To prepare a 1.00 L of a 4.90 M NaOH solution, you would need 200.05 g of NaOH.

Step-by-step explanation:

To calculate the grams of solute needed to prepare a 1.00 L of a 4.90 M NaOH solution, we can use the formula:

grams of solute = (Molarity x Volume x Molar mass) / 1000

First, we need to calculate the moles of NaOH needed:

(4.90 mol/L x 1.00 L) = 4.90 mol

Then, we can convert moles to grams using the molar mass of NaOH:

(4.90 mol NaOH x 40.0 g/mol) = 196 g

Therefore, the correct answer is option a) 200.05 g.