198,650 views
34 votes
34 votes
A probability experiment consist of rolling a 15-sided die. Find the probability of the event below. rolling a number divisible by 6

User Steeve
by
2.6k points

2 Answers

24 votes
24 votes

Final answer:

The probability of rolling a number divisible by 6 on a 15-sided die is 2/15, given that there are two favorable outcomes (6 and 12) and 15 possible outcomes.

Step-by-step explanation:

The subject of this question is Mathematics, specifically the topic of probability. The grade level of this question is appropriate for Middle School. To find the probability of rolling a number divisible by 6 on a 15-sided die, you would identify the numbers on the die that are divisible by 6, which would be 6 and 12. That gives you two favorable outcomes.

The sample space, which is the total number of possible outcomes, is 15, as there are 15 distinct sides on the die. The probability of an event is calculated as the number of favorable outcomes divided by the sample space. Therefore, the probability (P) of rolling a number divisible by 6 on a 15-sided die is:

P = Number of favorable outcomes / Sample space

P = 2 / 15

The answer to this question is that the probability of rolling a number divisible by 6 on a 15-sided die is 2/15.

User Brogan
by
2.7k points
19 votes
19 votes

SOLUTION

A 15-sided die has 15 faces numbered 1 to 15.

So the total possible outcome is 15.

Of all the numbers from 1 to 15, only 6 and 12 are divisible by 6. Therefore the numbers divisible by 6 is 2.

So the required outcome = 2

Probability =


\text{Probability = }\frac{required\text{ outcome}}{\text{total possible outcome}}

So,


\begin{gathered} \text{Probability = }\frac{required\text{ outcome}}{\text{total possible outcome}} \\ \\ \text{Probability = }\frac{2}{\text{1}5} \end{gathered}

User Kimh
by
3.0k points