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Determine the expression for the activity of zn in the fcc solid solution as a function of mole fraction of zn A) a_Zn = (x_Zn²) / a_Zn

B) a_Zn = x_Zn

C) a_Zn = 1 / x_Zn

D) a_Zn = x_Zn²

User Vu Anh
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Final answer:

The expression for the activity of zinc in an FCC solid solution as a function of the mole fraction of zinc is a_Zn = x_Zn.

Step-by-step explanation:

The question is asking for the expression that describes the activity (a_Zn) of zinc in a face-centered cubic (FCC) solid solution as a function of the mole fraction of zinc (x_Zn). In many solid solutions, particularly those that follow Raoult's law or Henry's law in the limit of dilute solutions, the activity of a component is proportional to its mole fraction within the solution. Therefore, the correct expression for this would be linear with the mole fraction:

a_Zn = x_Zn

None of the other options (a_Zn = (x_Zn2) / a_Zn, a_Zn = 1 / x_Zn, a_Zn = x_Zn2) reflect Raoult's or Henry's law for the activity in solid solutions correctly. Thus, the accurate answer is B) a_Zn = x_Zn.

User Puttu
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