Final answer:
The concentration of the new solution after diluting 4.5 mL of a 0.345M CoCl2 solution with 5.5 mL of water is 0.15525 M. The dilution is calculated using the formula M1V1 = M2V2, which maintains the conservation of moles.
Step-by-step explanation:
The student has asked a question related to the dilution of a solution in Chemistry. To calculate the concentration of the new diluted solution, we use the principle of conservation of moles, which states that the number of moles of solute remains the same before and after dilution. The formula M1V1 = M2V2 is often used, where M1 and V1 are the initial molarity and volume of the solution, and M2 and V2 are the molarity and volume of the diluted solution, respectively.
In the provided question, 4.5 mL of a 0.345M solution of CoCl2 is diluted with 5.5 mL of water. The total volume after dilution V2 is the sum of the volumes of the solution and water, which is 4.5 mL + 5.5 mL = 10.0 mL. Using the dilution equation:
- M1V1 = M2V2
- (0.345 M)(4.5 mL) = (M2)(10.0 mL)
- M2 = (0.345 M)(4.5 mL) / 10.0 mL
- M2 = 1.5525 / 10.0
- M2 = 0.15525 M
Therefore, the concentration of the new diluted solution is 0.15525 M.