Question

a 15 gram sample of lithium is reacted with 15 gram of fluorine to form lithium fluoride: 2li f2 → 2lif. after the reaction is complete, what will be present?

Answer 1

After the reaction, lithium fluoride (LiF) will be present.

Step-by-step explanation:

When 15 grams of lithium (Li) reacts with 15 grams of fluorine (F2), it forms 2 moles of lithium fluoride (LiF) according to the equation 2Li + F2 → 2LiF. In this reaction, both lithium and fluorine lose and gain electrons respectively to achieve a stable electron configuration. After the reaction is complete, what will be present is the 15 grams of lithium fluoride (LiF).

Answer 2

After reacting 15 grams of lithium with 15 grams of fluorine to form lithium fluoride, the amount of each product or any leftover reactants depends on the limiting reactant, which can be found via stoichiometric calculations.

Step-by-step explanation:

When 15 grams of lithium is reacted with 15 grams of fluorine, lithium fluoride (LiF) forms as a result of a chemical reaction. Since both elements are highly reactive and have the desire to acquire a stable valence electron configuration, lithium will donate an electron while fluorine will gain an electron, forming an ionic compound where lithium ions have a +1 charge and fluorine ions have a -1 charge.

However, to determine what will be present after the reaction, one needs to identify the limiting reactant. This can be done by calculating the moles of each reactant using their molecular weights (Li has a molar mass of approximately 6.94 g/mol, and F2 has a molar mass of approximately 38.00 g/mol). Then compare the stoichiometry of the balanced equation 2Li + F2 → 2LiF to find out which reactant will be fully consumed first.