Question

When tightening a bolt, you push perpendicularly on a wrench with a force of 157 N at a distance of 0.120 m from the center of the bolt.

a) 18.84 N
b) 13.25 N
c) 9.42 N
d) 5.43 N

Answer 1

The torque exerted when applying a force of 165 N at a distance of 0.140 m from the bolt centre is 23.1 Newton meters. This corresponds to approximately 17.04 foot-pounds.

Step-by-step explanation:

When tightening a bolt, exerting a force perpendicularly on a wrench is a classic example of applying a torque. Torque, often measured in Newton meters (N.m), is calculated as the product of the force applied and the distance from the pivot point, expressed as Torque = Force x Distance. To find the torque you are exerting when applying a force of 165 N at a distance of 0.140 m from the centre of the bolt, you simply multiply the force by the distance:
Torque = 165 N x 0.140 m = 23.1 N.m
Converting this torque into foot-pounds involves using the conversion factor that 1 Newton meter equals approximately 0.73756 foot-pounds:
Torque in foot-pounds = 23.1 N.m x 0.73756 = Approximately 17.04 foot-pounds.