Question

Hi , can you help me please , I did the run and ride the results is y=-4/3x + 4/3. what would the graph look like with ours results?

Answer 1

Given the equation of a straight line below

`y=-(4)/(3)x+(4)/(3)`

The general equation of a line,

`y=mx+c_{}`

Where

`\begin{gathered} m\text{ is the slope of the line} \\ c\text{ is the y-intercept} \end{gathered}`

The slope, m, of the given line is

`m=-(4)/(3)`

The graph of the equation of the line given is shown below

Hence, the slope of the given equation of a line is, m = -4/3