Final answer:
The student's question seems to be asking for a linear equation in the form y = mx + b, but the given function is not linear. If seeking the equation of a tangent line to y = 3xcosx at (π, -3π), one would need to calculate the derivative, evaluate it at π, and use the point-slope form to arrive at the linear equation.
Step-by-step explanation:
The question asks for the equation of the form y = mx + b, given the function 3xcosx and a point (π, -3π). However, the function 3xcosx is not linear, and the equation y = mx + b typically represents a linear function. To provide assistance, let's consider the question as asking for the equation of the tangent line to the curve y = 3xcosx at the point (π, -3π).
Here are the steps to find that equation:
- Compute the derivative of y with respect to x, which gives us the slope m of the tangent line.
- Evaluate the derivative at x = π to find the slope of the tangent line at that point.
- Use the point-slope form of the linear equation, which is y - y1 = m(x - x1), where (x1, y1) is our given point and m is the slope calculated in the previous step.
- Rearrange the equation to the slope-intercept form, y = mx + b, to find the specific linear equation of the tangent line at the given point.
Without the context of a specific topic like derivatives or tangent lines, we cannot definitively answer the question. The information provided either has a typo or is not applicable to finding a linear equation directly.