Final answer:
When the even integer n is divided by 9 and the remainder is 8, adding 10 to n gives a sum that is divisible by 18.
Step-by-step explanation:
When an even integer n is divided by 9, the remainder is 8. We need to find which of the given numbers, when added to n, gives a sum that is divisible by 18.
To solve this, we can think of the divisibility rule of 18, which states that for a number to be divisible by 18, it must be divisible by both 9 and 2. Since we already know that n leaves a remainder of 8 when divided by 9, we can add the given numbers one by one and check if the sum is divisible by 18.