Final answer:
The pressure of the water vapor after removing the partition and transferring enough heat can be determined using the ideal gas law. The pressure is calculated to be 7.90 kPa.
Step-by-step explanation:
The pressure of the water vapor after the partition has been removed and enough heat has been transferred so that the temperature of the water is 5˚C can be determined using the ideal gas law. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Since the right side of the chamber is initially evacuated, the volume of the left side is double that of the right side. Therefore, the total volume of the chamber is 3 times the volume of the left side.
Using the ideal gas law, we can set up the following equation:
PV = (1 mol)(8.314 J/(mol·K))(5+273.15 K)
Since the volume of the left side is V and the total volume of the chamber is 3V, we can rewrite the equation as:
P(3V) = (1 mol)(8.314 J/(mol·K))(5+273.15 K)
Simplifying the equation, we get:
PV = 3(8.314)(278.15)
Solving for P, we find:
P = 7.90 kPa (rounded to two decimal places)