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A restaurant in your town had 163 diners on Friday night. By Monday evening, 24 of those diners had reported to the Emergency Department, outpatient clinics, or saw their physicians with symptoms of gastrointestinal distress, suggesting food poisoning. Stool cultures for Salmonella were positive in all 24 diners. What is the estimated* probability of a diner having contracted food poisoning at that restaurant on that Friday night

User Aschab
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Final answer:

The estimated probability of a diner contracting food poisoning at the restaurant on that Friday night is 14.72%, calculated by dividing the 24 diners who became ill by the total 163 diners.

Step-by-step explanation:

To calculate the estimated probability of a diner contracting food poisoning at the restaurant on that Friday night, we can use the information provided.

Out of 163 diners, 24 reported symptoms of gastrointestinal distress and had stool cultures positive for Salmonella. The estimated probability can be found by dividing the number of diners who became ill by the total number of diners.

Probability = Number of diners who became ill ÷ Total number of diners

Probability = 24 ÷ 163

Probability = 0.1472, or 14.72%

Therefore, the estimated probability of a diner contracting food poisoning after eating at the restaurant is 14.72%.

User Pazcal
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