Question

Please help me because I am unable to find help and I have to turn in this assignment or else I will fail this class for the year.

Answer 1

Step-by-step explanation:

To solve this question, we need to use the following equation:

M = n/V

where:

M = molarity

n = number in moles

V = volume

For trial 1 we have:

M of NaOH = 0.112 mol/L

n = ??

V = 7.18 mL (we need to transform it to L, just divide by 1000)

V = 0.718 L

So:

M = n/V

n = M*V

n = 0.112*0.718

n = 0.080 moles of NaOH

The equation of dissociation of NaOH is:

NaOH --> Na+ + OH-

0.080 0.080 0.080

Answer for trial one: 0.080 moles of OH- or 8.0x10^-2 moles

For trial 2 we have:

For trial 1 we have:

M of NaOH = 0.112 mol/L

n = ??

V = 7.20 mL (we need to transform it to L, just divide by 1000)

V = 0.720 L

So:

M = n/V

n = M*V

n = 0.112*0.720

n = 0.081 moles of NaOH

The equation of dissociation of NaOH is:

NaOH --> Na+ + OH-

0.081 0.081 0.081

Answer for trial two: 0.081 moles of OH- or 8.1x10^-2 moles