Final answer:
The time taken for a pseudo first-order reaction can be solved using the second-order half-life equation. In this case, the reaction is second order, has a reactant concentration of 0.200 mol L-1, and a rate constant of 0.0576 L mol-1 min-1. Substituting these values gives a half-life of 18 min.
Step-by-step explanation:
The reaction in question is second order, is initiated with a 0.200 mol L-1 reactant solution, and exhibits a rate constant of 0.0576 L mol-1 min-1. Substituting these quantities into the second-order half-life equation:
t1/2 = 18 min