Question

A thin 2.82 m long copper rod in a uniform magnetic field has a mass of 44.2 g. When the rod carries a current of 0.238 A, it floats in the magnetic field. The acceleration of gravity is 9.81 m/s². What is the field strength of the magnetic field?

Answer 1

To find the field strength of the magnetic field, use the formula F = BIL and solve for B.

Step-by-step explanation:

To find the field strength of the magnetic field, we can use the formula F = BIL, where F is the force experienced by the copper rod, B is the magnetic field strength, I is the current, and L is the length of the rod.

In this case, the force experienced by the rod is equal to its weight when it is floating, so we can write the equation as mg = BIL.

Solving for B, we have B = mg/IL. Plugging in the values (mass = 44.2 g = 0.0442 kg, length = 2.82 m, and current = 0.238 A), we get B = (0.0442 kg * 9.81 m/s^2)/(0.238 A * 2.82 m) = 0.569 T.