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The collar slides on the circular bar with a constant angular velocity of 0.6 rad/s. The radial position is given as a function (m). Find the magnitude of the velocity at (63^˚).

a) (V = 0.6 , textm/s)

b) (V = 0.6 , textrad/s)

c) (V = 0.6 , textm/s^2)

d) (V = 0.6 , textrad/s^2)

User Lucchi
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1 Answer

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Final answer:

To find the magnitude of the velocity at 63 degrees, convert the angular velocity from radians per second to degrees per second, then use the formula v = r * ω to calculate the magnitude of the velocity at the given radial position.

Step-by-step explanation:

To find the magnitude of the velocity at 63 degrees, we can start by converting the angular velocity from radians per second to degrees per second. Since 1 radian is equal to 57.3 degrees, we can multiply the angular velocity of 0.6 rad/s by 57.3 to get the angular velocity in degrees per second. The result is approximately 34.38 degrees per second.

Since the velocity is tangential to the circular path, the magnitude of the velocity at a specific radial position can be calculated using the formula:

v = r * ω

where v is the magnitude of the velocity, r is the radial position, and ω is the angular velocity in degrees per second. Using this formula and plugging in the given values, we can calculate the magnitude of the velocity at 63 degrees.

User Martin Clarke
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