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Hydrogen gas(H2)occupies a volume of 100.0ml at 27C and 300 torr. What pressure will it have its cooled to 73C and the volume remains constant V. 100.0ml?

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Final answer:

To calculate the new pressure of hydrogen gas when cooled from 27°C to 73°C with constant volume, we apply Gay-Lussac's law. This involves using the initial and final temperatures in kelvins and the initial pressure to find the final pressure.

Step-by-step explanation:

The question asks about the behavior of a sample of hydrogen gas when it undergoes a temperature change while its volume remains constant. According to Gay-Lussac's law (which is a derivation of the combined gas law for constant volume), the pressure of a gas is directly proportional to its temperature in kelvins. Using this principle, the new pressure of hydrogen gas cooled from 27°C to 73°C can be calculated. The calculations will use the initial pressure (300 torr), the initial temperature (27°C, which is 300.15 K), and the final temperature (73°C, which is 346.15 K). The formula to use is P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

To find the final pressure (P2), we rearrange the formula to P2 = P1 × (T2/T1), then plug in the values and solve for P2.

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