Final Answer:
The volume of the propane sample at 1.12 atm and 95 degrees Celsius is 369.77 L.
Step-by-step explanation:
We can use the combined gas law to solve for the volume of the propane sample at the new conditions. The combined gas law states that:
(P1V1)/T1 = (P2V2)/T2
where:
P1 is the initial pressure (1.35 atm)
V1 is the initial volume (250.0 L)
T1 is the initial temperature (311 K)
P2 is the final pressure (1.12 atm)
V2 is the final volume (unknown)
T2 is the final temperature (368 K)
Plugging in the known values, we get:
(1.35 atm)(250.0 L)/(311 K) = (1.12 atm)(V2)/(368 K)
Solving for V2, we get:
V2 = (250.0 L)(1.12 atm)(368 K)/(1.35 atm)(311 K) = 369.77 L
Therefore, the volume of the propane sample at 1.12 atm and 95 degrees Celsius is 369.77 L.