Question

Give the hybridizations of the carbons, from left to right, in CH₃CH=CHCl.

Answer 1

The hybridizations of the carbons in CH₃CH=CHCl, from left to right, are sp³, sp², sp², sp³.

Step-by-step explanation:

In the molecule CH₃CH=CHCl, the carbon atoms from left to right have the following hybridizations:

The first carbon (CH₃) has four sigma bonds and no double bonds or lone pairs, so its hybridization is sp³.

The second carbon (CH=) has three sigma bonds, one pi bond, and no lone pairs, so its hybridization is sp².

The third carbon (=CH) has three sigma bonds, one pi bond, and no lone pairs, so its hybridization is sp².

The fourth carbon (Cl) has four sigma bonds and no double bonds or lone pairs, so its hybridization is sp³.