Final answer:
The balanced net ionic equation for the reaction is 2Na+(aq) + Pb2+(aq) + 2NO3-(aq) + S2-(aq) → PbS(s) + 2Na+(aq) + 2NO3-(aq), where sodium cation and nitrate anion are spectator ions.
Step-by-step explanation:
The balanced net ionic equation for the reaction between aqueous sodium sulfide (Na2S) and aqueous lead(II) nitrate (Pb(NO3)2) can be written as:
2Na+ (aq) + Pb2+ (aq) + 2NO3- (aq) + S2- (aq) → PbS (s) + 2Na+ (aq) + 2NO3- (aq)
The net ionic equation shows only the species that are directly involved in the reaction. In this case, the sodium cation (Na+) and the nitrate anion (NO3-) are spectator ions and do not participate in the formation of the solid precipitate (PbS).