Question

An electron has a constant acceleration of +3.2m/s². At a certain instant, its velocity is +9.6 m/s. What was its velocity 2.5s earlier?

Answer 1

The velocity of the electron 2.5 seconds earlier was +1.6 m/s.

Step-by-step explanation:

To find the velocity of the electron 2.5 seconds earlier, we can use the equation:

vf = vi + at

Where:

• vf is the final velocity
• vi is the initial velocity
• a is the acceleration
• t is the time

Given that the acceleration is +3.2 m/s² and the current velocity is +9.6 m/s, we can substitute these values into the equation:

vf = 9.6 + (3.2)(-2.5)

vf = 9.6 - 8

vf = 1.6 m/s

Therefore, the velocity of the electron 2.5 seconds earlier was +1.6 m/s.