Final answer:
To find the length of the longest repeating segment in an array, maintain a current segment length and update the maximum length when a longer segment is found. Iterate through the array, comparing adjacent elements, and update lengths accordingly. A sample implementation is provided in Java.
Step-by-step explanation:
The method in question is intended to find the length of the longest repeating segment in an array. To complete the implementation, we need to check each element of the array and compare it to the next one to find repeating segments. Once a repeating segment is found, we can calculate its length and update the length of the longest repeating segment if it's greater than the previously found segments.
To do this, we'll maintain two variables: currentLength for the length of the current segment and maxLength for the length of the longest repeating segment found so far. Initially, both variables will be set to 1. As we iterate through the array, we'll compare each element with the next one. If they are the same, we increment currentLength. If not, we reset currentLength to 1. Whenever currentLength exceeds maxLength, we update maxLength.
Example Implementation:
public int getLengthOfLongestRepeatingSegment(int[] array) {
if(array == null || array.length == 0) return 0;
int maxLength = 1;
int currentLength = 1;
for(int i = 1; i < array.length; i++) {
if(array[i] == array[i-1]) {
currentLength++;
} else {
maxLength = Math.max(maxLength, currentLength);
currentLength = 1;
}
}
maxLength = Math.max(maxLength, currentLength); // Check last segment
return maxLength;
}