Question

A sample of an ideal gas at 1.00 atm and a volume of 1.36 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 25.0 atm, what was the volume of the sample? Assume that the temperature was held constant. V = L​

Answer 1

When the pressure of the gas increases to 25.0 atm, the volume of the sample is 0.0544 L.

Step-by-step explanation:

In this question, the volume of a sample of gas is initially 1.36 L at a pressure of 1.00 atm. As the gas descends into the ocean, the water pressure compresses the balloon and reduces its volume. We are asked to find the volume of the sample when the pressure reaches 25.0 atm.

Using Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature, we can set up the equation:

P1V1 = P2V2

Substituting the given values into the equation:

(1.00 atm)(1.36 L) = (25.0 atm)(V2)

Solving for V2:

V2 = (1.00 atm)(1.36 L) / (25.0 atm)

V2 = 0.0544 L

Therefore, when the pressure reaches 25.0 atm, the volume of the sample is 0.0544 L.