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Women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches.

a. If a woman is randomly selected, find the probability that her height is less than 69.8 inches.
b. If 70 women are randomly selected, find the probability that they will have a mean height of less than 69.8 inches.

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Final answer:

a. The probability that a randomly selected woman's height is less than 69.8 inches is approximately 0.992 or 99.2%. b. The probability that 70 randomly selected women will have a mean height of less than 69.8 inches is approximately 0.993 or 99.3%.

Step-by-step explanation:

a. To find the probability that a randomly selected woman's height is less than 69.8 inches, we need to calculate the z-score and then use the standard normal distribution table. The formula for calculating the z-score is: z = (x - mean) / standard deviation. Plugging in the given values, we get: z = (69.8 - 63.6) / 2.5 = 2.48. From the standard normal distribution table, we find that the probability corresponding to a z-score of 2.48 is approximately 0.992. Therefore, the probability that a randomly selected woman's height is less than 69.8 inches is approximately 0.992 or 99.2%.

b. To find the probability that 70 randomly selected women will have a mean height of less than 69.8 inches, we need to calculate the z-score for the sample mean. The formula for calculating the z-score for a sample mean is: z = (x - mean) / (standard deviation / sqrt(n)), where n is the sample size. Plugging in the given values, we get: z = (69.8 - 63.6) / (2.5 / sqrt(70)) = 2.488. From the standard normal distribution table, we find that the probability corresponding to a z-score of 2.488 is approximately 0.993. Therefore, the probability that 70 randomly selected women will have a mean height of less than 69.8 inches is approximately 0.993 or 99.3%.

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