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The volume of a gas is increased six times the original volume by heating it. If the original temperature of the gas was 27 °C, what is the final temperature of the gas?

a. 1200°C
b. 1800°C
c. 1527°C
d. 1500

User Csj
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1 Answer

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Final answer:

Using Charles's Law, the final temperature of the gas with a volume increased six times from the original volume at 27 °C will be 1527 °C.

Step-by-step explanation:

The question pertains to Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is held constant. To find the final temperature of the gas when the volume is increased six times, we must first convert the original temperature to Kelvin. The original temperature is 27 °C, which is 273 + 27 = 300 K. According to Charles's Law, if the volume is increased six times, the final temperature must also be increased six times. Therefore, the final temperature in Kelvin is 300 K × 6 = 1800 K. To convert this back to Celsius, we subtract 273, giving us a final temperature of 1800 K - 273 = 1527 °C.

User Evens
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