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What is the molarity of hydrochloric acid in a solution containing 79.1 g of HCl in 295 mL of solution?

User Hew Wolff
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Final answer:

The molarity of hydrochloric acid in the solution is approximately 7.34 M.

Step-by-step explanation:

The molarity of hydrochloric acid in a solution can be calculated using the formula:

M = (n/HCl) / V

where M is the molarity, n is the number of moles of HCl, and V is the volume of the solution in liters.

First, we need to calculate the number of moles of HCl using the given mass of HCl and its molar mass:

n = mass / molar mass = 79.1 g / 36.5 g/mol = 2.167 mol

Next, we convert the volume of the solution from milliliters to liters:

V = 295 mL / 1000 mL/L = 0.295 L

Finally, we can plug in the values into the formula:

M = (2.167 mol) / (0.295 L) ≈ 7.34 M

User Sabumnim
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