Find the geometric mean of the sequence: 2112,______,33

Frennetix asked Aug 2, 2023

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Frennetix asked Aug 2, 2023

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24 votes

The sequence first term is a = 2112 and last term is b = 33.

The formula for the geometric mean is,

$\sqrt[]{a\cdot b}$

Determine the geometric mean of 2112 and 33.

$\begin{gathered} \sqrt[]{2112\cdot33}=\sqrt[]{69696} \\ =264 \end{gathered}$

So geometric sequence is 264.

Answer: 264

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