Final answer:
Mpho has 60 coins of 25 thebe and 85 coins of 10 thebe in her coin box. We found this by setting up an algebraic equation based on the given values and solving for the number of each type of coin.
Step-by-step explanation:
In her coin box, Mpho has 23.50 consisting of 25 thebe and 10 thebe coins. The number of 10 thebe coins is 25 more than the number of 25 thebe coins. To find out how many coins of each kind she has, let's use algebra.
Let the number of 25 thebe coins be x. Then the number of 10 thebe coins is x + 25. The total value of the coins is the value of the 25 thebe coins (25x thebe) plus the value of the 10 thebe coins (10(x + 25) thebe), which equals 23.50 or 2350 thebe (since P1 = 100 thebe).
So our equation to solve is:
25x + 10(x + 25) = 2350
Expanding the expression we get:
25x + 10x + 250 = 2350
35x + 250 = 2350
35x = 2100
x = 60
So there are 60 coins of 25 thebe. The number of 10 thebe coins is x + 25 which equals 60 + 25 = 85.
Therefore, Mpho has 60 coins of 25 thebe and 85 coins of 10 thebe in her coin box.