Final answer:
Simon can place 12 of the same type of item on each wreath, as 12 is the greatest common divisor (GCD) of the quantities of items he has.
Step-by-step explanation:
The question seems to be asking how Simon can distribute different items evenly across wreaths he is making. To determine how many items Simon can put on each wreath, we need to find the greatest common divisor (GCD) for the quantities of items he has. Simon has 60 bows, 36 silk flowers, and 48 silk carnations. To find the GCD of these numbers, we start by listing the factors of each number and then find the largest factor that is common to all three numbers.
Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
The largest common factor for these numbers is 12, so Simon can put 12 of the same type of item on each wreath.