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In order for th parallelogram tobe a square, x = = [? ]°4x+17°

In order for th parallelogram tobe a square, x = = [? ]°4x+17°-example-1
User Arkanosis
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1 Answer

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We know that the diagonals of a square bisects it's angles and every angles of square are 90°.

The diagnol bisects the parallelogram in two equal parts.

The angle obtained are,


4x+17^(\circ)

The sum of the angles are 90 deg.


4x+17+4x+17=90^(\circ)
8x+34=90^(\circ)
8x=56^(\circ)
x=7^(\circ)

Thus the value of x is 7 deg.

User Ncremins
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